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Lesson Plans - Grade 7 Math


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A number like this [1.2.2] is a state benchmark for math. Click it to link to the benchmarks.
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6-11-2001
1. HWP391 MidChRev..2. P395 1-3.........3. .................
4. .................5. .................6. .................

OBJECTIVE: Find the volume of rectangular prisms(105, Pp394ff)[1.2.1] ACTIVITIES: Review the difference between surface area and volume. Show the relationship between the traditional formula and the more generic V=B*h NOTES: HOMEWORK: Page 396, 9-17 (start in class)

6-12-2001
1. HW396 9-17.......2. P399 11-16.......3. .................
4. .................5. .................6. .................

OBJECTIVE: Find the volume of cylinders(10-6, Pp398ff)[1.2.1] ACTIVITIES: Relate the procedure to yesterday. Especially the generic form. NOTES: Review and do page 399 11-16 HOMEWORK: p594 #8 do the volume and surface area
[Interactive Graphic Cylinder Solver]Link Graphic

6-13-2001
1. HW594#8 sp.......2. .................3. .................
4. .................5. .................6. .................

OBJECTIVE: Solve problems by using a formula(10-7, Pp402ff) ACTIVITIES:[Distribute Progres Report #16] Emphasis is on selecting the appropriate formula and then substituting values. Pages 402 to 403, 1-9 NOTES: HOMEWORK: Pp405-406 12, 15, 18, 21

6-14-2001
1. ProgReport #16...2. HW405-6 x3x......3. P407 Ch10 Test...
4. .................5. .................6. .................

OBJECTIVE: Review ACTIVITIES: Chapter test Page 407 NOTES: HOMEWORK: Surface area and volume of a compound shape.

Compound shape
6-15-2001
1. HW Compound Shp..2. P480 3-12........3. .................
4. .................5. .................6. .................

OBJECTIVE: Solve problems involving discount and sales tax(12-8, Pp479ff) [1.1.1][3.1.2] ACTIVITIES: Review the procedures for percentages adn proportions, especially the percentage proportion. Do page 480 3-12 NOTES: HOMEWORK: Pp480-1 12-24 x2

Solutions grid: Cylinders Surface - Make one for EACH problem
Formulas:  [Circumference]  C = PI x d  [Diameter/Radius] d = 2 x r and r = d ÷ 2
[Circle]   A = PI x r2  [Rectangle]   A = lw  [PI]   PI = 3.14 or 22/7
Face/Part (Samples listed) Formula Substitute
Values in Formula
Sub-Answer
(include units)
Top A = PI x r2 A = 3.14 x ___2 A = ____ un2
Bottom A = PI x r2 A = 3.14 x ___2 A = ____ un2
Cylinder A = l x w
A = C x h (C = PI x d)
A = 3.14 x ____ x _____ A = ______un2
Total Surface Area     _______ un2


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Make Up Work Options [Replacement Problems]Link Graphic

Time permitting, Mr. LeMieux will post problems which can be used to replace some of the assignments students have chosen to not do. Since this is inherently unfair to those students who have completed their assignments on time, students' replacement work will be held to the highest standard of neatness and completeness. Sloppy, last minute attempts will be rejected. Students must review and follow the guidelines listed below. Diagrams, tables, and illustrations are encouraged. Labels and answer statements are required. None of these procedures are new. They have been emphasized all year.

Credit will be granted at the rate of 1 credit for each two, complete solutions. The accuracy of the answer as a requirement will be left entirely at the discretion of Mr. LeMieux. These problems are entirely voluntary.

[How to write a solution]Link Graphic [Written problem scoring guide]Link Graphic
Unexplained answers receive NO credit!

[standard guidelines]Link Graphic